Linear Equation Solver (ax + b = c)
Understanding Linear Equations and How to Solve Them
A linear equation is an algebraic equation in which each term has an exponent of one and the graphing of the equation results in a straight line. The most common form for a single-variable linear equation is ax + b = c, where 'x' is the variable, and 'a', 'b', and 'c' are constants.
Components of a Linear Equation:
- 'x' (Variable): This is the unknown value we aim to find.
- 'a' (Coefficient): This number multiplies the variable 'x'. If 'a' is 0, the equation is no longer truly linear in 'x'.
- 'b' (Constant Term): This is a fixed number added to the 'ax' term on the left side of the equation.
- 'c' (Constant Term): This is a fixed number on the right side of the equation.
How to Solve ax + b = c:
The goal is to isolate 'x' on one side of the equation. Here are the steps:
- Subtract 'b' from both sides: This moves the constant 'b' from the left side to the right side.
ax + b - b = c - bax = c - b - Divide both sides by 'a': This isolates 'x'.
ax / a = (c - b) / ax = (c - b) / a
Special Cases:
- If 'a' is 0:
- If
0x = 0(meaningc - b = 0), then there are infinitely many solutions, as any value of 'x' will satisfy the equation. - If
0x = (a non-zero number)(meaningc - b ≠ 0), then there is no solution, as 0 multiplied by any number can never equal a non-zero number.
- If
Using the Calculator:
Our Linear Equation Solver helps you quickly find the value of 'x' for equations in the form ax + b = c. Simply input the values for 'a', 'b', and 'c' into the respective fields, and the calculator will apply the algebraic steps to determine 'x'.
Examples:
Let's look at a few examples:
Example 1: Simple Solution
- Equation:
2x + 5 = 15 - Input 'a':
2 - Input 'b':
5 - Input 'c':
15 - Calculation:
x = (15 - 5) / 2 = 10 / 2 = 5 - Result:
x = 5
Example 2: Negative Numbers
- Equation:
-3x + 7 = 1 - Input 'a':
-3 - Input 'b':
7 - Input 'c':
1 - Calculation:
x = (1 - 7) / -3 = -6 / -3 = 2 - Result:
x = 2
Example 3: No Solution
- Equation:
0x + 4 = 9 - Input 'a':
0 - Input 'b':
4 - Input 'c':
9 - Calculation:
0x = 9 - 4 => 0x = 5. This is impossible. - Result:
No Solution
Example 4: Infinite Solutions
- Equation:
0x + 6 = 6 - Input 'a':
0 - Input 'b':
6 - Input 'c':
6 - Calculation:
0x = 6 - 6 => 0x = 0. Any 'x' works. - Result:
Infinite Solutions