Note: This calculator estimates the total Pokéyen and items required to breed a Pokémon from scratch (starting with 1×31 IV parents) to your desired target.
Unlike standard Pokémon games, PokeMMO uses a "consumptive" breeding system. When you breed two Pokémon, the parents are lost forever, and you receive an egg. This makes building competitive 5×31 or 6×31 Pokémon a resource-intensive process requiring careful planning and significant Pokéyen.
Core Mechanics of the Calculator
IV Inheritance: To guarantee an IV transfers to the offspring, the parent must hold a "Power Item" (Brace). If both parents have 31 in a stat and both hold the corresponding brace, the baby will have 31. If you are combining different stats (e.g., HP and Attack), you use one brace for each.
Everstones: These are used to lock in a specific Nature. In PokeMMO, nature locking is expensive because you must maintain the nature throughout the entire breeding tree.
Gender Selection: Since you need a male and female of the same egg group to breed, you often have to pay the Daycare lady to ensure the baby is the correct gender for the next step in your chain.
Breeding Math Example: 5×31 Pokemon
To create a 5×31 Pokémon, you follow an exponential path:
Create eight 2×31 Pokémon from sixteen 1×31 parents.
Create four 3×31 Pokémon from those eight 2x31s.
Create two 4×31 Pokémon from those four 3x31s.
Finally, create one 5×31 Pokémon from the two 4x31s.
This process requires 15 total breeds. Each breed requires gender selection (except the final step) and two Power items (costing 10,000 each).
Tips for Saving Pokéyen
1. Catch your own fodder: Instead of buying 1×31 parents from the GTL, spend time catching Pokémon in the wild. This significantly reduces the "Parent Price" in the calculator.
2. Field Egg Group: Many competitive Pokémon belong to the Field egg group. Smeargle is a popular choice for "male fodder" because it can breed with a wide variety of species.
3. Nature last? It is often cheaper to find a parent with the desired Nature and a 31 IV at the very beginning of the chain and use Everstones throughout, rather than trying to fix the nature at the end.
function calculateBreeding() {
var target = parseInt(document.getElementById("targetIVs").value);
var genderSelectCost = parseInt(document.getElementById("genderCost").value);
var includeNature = document.getElementById("includeNature").value;
var avgParentPrice = parseFloat(document.getElementById("parentPrice").value);
if (isNaN(avgParentPrice) || avgParentPrice < 0) {
alert("Please enter a valid parent price.");
return;
}
// Number of 1×31 parents needed is 2^(target-1)
// To get a 2×31, you need 2 1x31s.
// To get a 3×31, you need 4 1x31s.
// To get a 5×31, you need 16 1x31s.
var numParents = Math.pow(2, target – 1);
// Total breeds required to consolidate those parents
var totalBreeds = numParents – 1;
// Each breed requires 2 braces (10k each) until the very last steps
// Actually, simple math: every breed consumes 2 braces to pass down 2 different stats
var bracesCount = totalBreeds * 2;
var braceCost = bracesCount * 10000;
// Gender selection is needed for every breed except the final result
var genderSelectionTotalCost = (totalBreeds – 1) * genderSelectCost;
// Nature logic:
// If nature is included, one parent in every single breed step must hold an Everstone (5k)
// and the other parent holds a Power item (10k).
// This slightly changes the brace math because one slot is taken by Everstone.
var everstoneCount = 0;
var natureCost = 0;
if (includeNature === "yes") {
// You need to maintain nature from the start.
// In a tree, one side of every breed must carry the Everstone.
everstoneCount = totalBreeds;
natureCost = everstoneCount * 5000;
// If one parent holds Everstone, only one Power Brace is used per breed
// to pass the "new" stat, while the Everstone parent passes nature + its existing IVs naturally
// This is a simplified model of nature-chaining.
bracesCount = totalBreeds;
braceCost = bracesCount * 10000;
}
var totalParentInvestment = numParents * avgParentPrice;
var grandTotal = totalParentInvestment + braceCost + genderSelectionTotalCost + natureCost;
// Display Results
document.getElementById("breedingResult").style.display = "block";
document.getElementById("totalCost").innerText = "$" + grandTotal.toLocaleString();
document.getElementById("parentsNeeded").innerText = numParents;
document.getElementById("bracesNeeded").innerText = bracesCount;
document.getElementById("everstonesNeeded").innerText = everstoneCount;
}